Initialize a long in Java

java long-integer
aamadmi picture aamadmi · Jul 26, 2011 · Viewed 408.1k times · Source

Primitive Data Types - oracle doc says the range of long in Java is -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807. But when I do something like this in my eclipse

long i = 12345678910;

it shows me "The literal 12345678910 of type int is out of range" error.

There are 2 questions.

1) How do I initialize the long with the value 12345678910?

2) Are all numeric literals by default of type int?

Answer

MByD picture MByD · Jul 26, 2011
  1. You should add L: long i = 12345678910L;.
  2. Yes.

BTW: it doesn't have to be an upper case L, but lower case is confused with 1 many times :).

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