This is probably pretty basic, but to save me an hour or so of grief can anyone tell me how you can work out the number of bits required to represent a given positive integer in Java?
e.g. I get a decimal 11, (1011). I need to get the answer, 4.
I figured if I could work out how to set all the bits other than the most significant bit to 0, and then >>> it, I'd get my answer. But... I can't.
Well, the answer is pretty simple. If you have an int value:
int log2(int value) {
return Integer.SIZE-Integer.numberOfLeadingZeros(value);
}
The same exists for Long...
[Edit] If shaving milliseconds is an issue here, Integer.numberOfLeadingZeros(int) is reasonably efficient, but still does 15 operations... Expanding a reasonable amount of memory (300 bytes, static) you could shave that to between 1 and 8 operations, depending on the range of your integers.