This question is asked in numerous places, with myriad small variations. (Such as Java - getClassLoader().getResource() driving me bonkers among others.) I still can't make it work.
Here's a code snippet:
String clipName = "Chook.wav";
ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
// URL url = classLoader.getResource(clipName);
URL url = new URL("file:///Users/chap/Documents/workspace/the1620/bin/ibm1620/" + clipName);
ais = AudioSystem.getAudioInputStream(url);
This works -- note that I've hard-coded the path to the directory containing the clip file, which is there, and is in the same directory as my .class file. Alas, the commented-out code just returns a null value for url.
Most other posts seem to deal with getResourceAsStream(). I think I'm supposed to be using getResource(). Is that making the difference?
It just can't be this hard. Any clues?
String clipName = "Chook.wav";
When using getResource
, the string you pass in must be either an absolute name or be valid relative to a certain class. Since you're using ClassLoader.getResource()
and not Class.getResource()
, it must be an absolute path.
Without seeing your actual file hierarchy, I can only guess that "bin" is the root of your compiled classes and resources, and "ibm1260" is a package/folder within that path, and "Chook.wav" exists in that folder. If that's the case, then you need to use /ibm1260/Chook.wav
(or potentially ibm1260/Chook.wav
, I don't typically use the class loader for resource lookups) as the name of the file that you pass in to getResource()
.
Either way, you need to make sure that the file is copied into the location of your compiled code and that the root folder is on the classpath.