How does marking a field as transient make it possible to serialise an object

zengr picture zengr · Mar 3, 2011 · Viewed 38.7k times · Source
public class Foo implements java.io.Serializable {
   private int v1;
   private static double v2;
   private Loan v3 = new Loan();
}

Options:
A. An instance of Foo can be serialized because Foo implements Serializable.
B. An instance of Foo cannot be serialized because Foo contains a non-serializable instance variable v3.
C. If you mark v3 as transient, an instance of Foo is serializable.
D. b and c

Answer: D

Explanation: An object may not be serialized even though its class implements java.io.Serializable, because it may contain non-serializable instance variables.

Now my question is:

As far as I know, transient is used to turn off serialization. Then how is transient in this case, helping us to serialize foo?

Answer

cHao picture cHao · Mar 3, 2011

transient doesn't disable serialization altogether; it just marks members that won't be serialized. It's typically used for stuff that would be incorrect or irrelevant when the object is unserialized, or stuff that it'd be less-than-safe to store (passwords, decrypted data, that sort of thing), or non-serializable stuff that could be easily reconstructed.

In this case, i assume the Loan class isn't serializable. (If it were, then A would be correct.) Marking v3 as transient just tells Java not to worry about that field, but go ahead and serialize the others. This means an unserialized Foo might have a null v3. If you want to store the Loan as well, you'd need to either keep track of enough info to recreate it at will, or change class Loan so that it implements java.io.Serializable as well.

Alternatively, there are methods you could implement (writeObject, readObject) if you need control over serialization. But that can be a bit of a hassle.