I want to convert a hex string to long in java.
I have tried with general conversion.
String s = "4d0d08ada45f9dde1e99cad9";
long l = Long.valueOf(s).longValue();
System.out.println(l);
String ls = Long.toString(l);
But I am getting this error message:
java.lang.NumberFormatException: For input string: "4d0d08ada45f9dde1e99cad9"
Is there any way to convert String to long in java? Or am i trying which is not really possible!!
Thanks!
Long.decode(str)
accepts a variety of formats:
Accepts decimal, hexadecimal, and octal numbers given by the following grammar:
DecodableString:
- Signopt DecimalNumeral
- Signopt 0x HexDigits
- Signopt 0X HexDigits
- Signopt # HexDigits
- Signopt 0 OctalDigits
Sign:
- -
But in your case that won't help, your String is beyond the scope of what long can hold. You need a BigInteger
:
String s = "4d0d08ada45f9dde1e99cad9";
BigInteger bi = new BigInteger(s, 16);
System.out.println(bi);
Output:
23846102773961507302322850521
For Comparison, here's Long.MAX_VALUE
:
9223372036854775807