How to convert a hexadecimal string to long in java?

user405398 picture user405398 · Mar 1, 2011 · Viewed 87.3k times · Source

I want to convert a hex string to long in java.

I have tried with general conversion.

String s = "4d0d08ada45f9dde1e99cad9";
long l = Long.valueOf(s).longValue();
System.out.println(l);
String ls = Long.toString(l);

But I am getting this error message:

java.lang.NumberFormatException: For input string: "4d0d08ada45f9dde1e99cad9"

Is there any way to convert String to long in java? Or am i trying which is not really possible!!

Thanks!

Answer

Sean Patrick Floyd picture Sean Patrick Floyd · Mar 1, 2011

Long.decode(str) accepts a variety of formats:

Accepts decimal, hexadecimal, and octal numbers given by the following grammar:
DecodableString:

  • Signopt DecimalNumeral
  • Signopt 0x HexDigits
  • Signopt 0X HexDigits
  • Signopt # HexDigits
  • Signopt 0 OctalDigits

Sign:

  • -

But in your case that won't help, your String is beyond the scope of what long can hold. You need a BigInteger:

String s = "4d0d08ada45f9dde1e99cad9";
BigInteger bi = new BigInteger(s, 16);
System.out.println(bi);

Output:

23846102773961507302322850521

For Comparison, here's Long.MAX_VALUE:

9223372036854775807