I want to check a char variable is one of 21 specific chars, what is the shortest way I can do this?
For example:
if(symbol == ('A'|'B'|'C')){}
Doesn't seem to be working. Do I need to write it like:
if(symbol == 'A' || symbol == 'B' etc.)
Answer
If your input is a character and the characters you are checking against are mostly consecutive you could try this:
if ((symbol >= 'A' && symbol <= 'Z') || symbol == '?') {
// ...
}
However if your input is a string a more compact approach (but slower) is to use a regular expression with a character class:
if (symbol.matches("[A-Z?]")) {
// ...
}
If you have a character you'll first need to convert it to a string before you can use a regular expression:
if (Character.toString(symbol).matches("[A-Z?]")) {
// ...
}