Deserialize a json array to objects using Jackson and WebClient

Justin picture Justin · Feb 3, 2018 · Viewed 21.9k times · Source

I have a problem during the deserialization of a json array using Spring. I have this json response from a service:

[
    {
        "symbol": "XRPETH",
        "orderId": 12122,
        "clientOrderId": "xxx",
        "price": "0.00000000",
        "origQty": "25.00000000",
        "executedQty": "25.00000000",
        "status": "FILLED",
        "timeInForce": "GTC",
        "type": "MARKET",
        "side": "BUY",
        "stopPrice": "0.00000000",
        "icebergQty": "0.00000000",
        "time": 1514558190255,
        "isWorking": true
    },
    {
        "symbol": "XRPETH",
        "orderId": 1212,
        "clientOrderId": "xxx",
        "price": "0.00280000",
        "origQty": "24.00000000",
        "executedQty": "24.00000000",
        "status": "FILLED",
        "timeInForce": "GTC",
        "type": "LIMIT",
        "side": "SELL",
        "stopPrice": "0.00000000",
        "icebergQty": "0.00000000",
        "time": 1514640491287,
        "isWorking": true
    },
    ....
]

I get this json using the new WebClient from Spring WebFlux, here the code:

@Override
    public Mono<AccountOrderList> getAccountOrders(String symbol) {
        return binanceServerTimeApi.getServerTime().flatMap(serverTime -> {
            String apiEndpoint = "/api/v3/allOrders?";
            String queryParams = "symbol=" +symbol.toUpperCase() + "&timestamp=" + serverTime.getServerTime();
            String signature = HmacSHA256Signer.sign(queryParams, secret);
            String payload = apiEndpoint + queryParams + "&signature="+signature;
            log.info("final endpoint:"+ payload);
            return this.webClient
                    .get()
                    .uri(payload)
                    .accept(MediaType.APPLICATION_JSON)
                    .retrieve()
                    .bodyToMono(AccountOrderList.class)
                    .log();
        });
    }

AccountOrderList

public class AccountOrderList {

    private List<AccountOrder> accountOrders;

    public AccountOrderList() {
    }

    public AccountOrderList(List<AccountOrder> accountOrders) {
        this.accountOrders = accountOrders;
    }

    public List<AccountOrder> getAccountOrders() {
        return accountOrders;
    }

    public void setAccountOrders(List<AccountOrder> accountOrders) {
        this.accountOrders = accountOrders;
    }
}

AccountOrder is a simple pojo that maps the fields.

Actually, when I hit a get it says:

org.springframework.core.codec.DecodingException: JSON decoding error: Cannot deserialize instance of `io.justin.demoreactive.domain.AccountOrder` out of START_ARRAY token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `io.justin.demoreactive.domain.AccountOrder` out of START_ARRAY token
 at [Source: UNKNOWN; line: -1, column: -1]

How can I deserialize the json properly using the new webflux module? What am I doing wrong?

UPDATE 05/02/2018

Both answers are correct. They addressed perfectly my question but at the end I decided to use a slightly different approach:

@Override
    public Mono<List<AccountOrder>> getAccountOrders(String symbol) {
        return binanceServerTimeApi.getServerTime().flatMap(serverTime -> {
            String apiEndpoint = "/api/v3/allOrders?";
            String queryParams = "symbol=" +symbol.toUpperCase() + "&timestamp=" + serverTime.getServerTime();
            String signature = HmacSHA256Signer.sign(queryParams, secret);
            String payload = apiEndpoint + queryParams + "&signature="+signature;
            log.info("final endpoint:"+ payload);
            return this.webClient
                    .get()
                    .uri(payload)
                    .accept(MediaType.APPLICATION_JSON)
                    .retrieve()
                    .bodyToFlux(AccountOrder.class)
                    .collectList()
                    .log();
        });
    }

An alternative to this could be to return directly A Flux so you don't have to convert it to a list. (that's what flux are: a collection of n elements).

Answer

Pin picture Pin · Jan 3, 2019

Regarding your updated answer to your question, using bodyToFlux is unnecessarily inefficient and semantically doesn't make much sense either as you don't really want a stream of orders. What you want is simply to be able to parse the response as a list.

bodyToMono(List<AccountOrder>.class) won't work due to type erasure. You need to be able to retain the type at runtime, and Spring provides ParameterizedTypeReference for that:

bodyToMono(new ParameterizedTypeReference<List<AccountOrder>>() {})