Why is Class<?> preferred to Class
If I declare a Class as a field:
Class fooClass;
Eclipse gives me the warning:
Class is a raw type. References to generic type Class should be parametrized
What does this mean in practice? and why am I urged to do it? If I ask Eclipse for a "quick fix" it gives me:
Class<?> fooClass;
which doesn't seem to add much value but no longer gives a warning.
EDIT: Why is Class generic? Could you please give an example of parameterization, i.e. could there be a valid use of something other than <?> ?
EDIT: WOW! I had not realized the depths of this. I have also watched the Java Puzzler and it's certainly scared me about the bear traps. So I will always use
Class<MyString> myStringClass = MyString.class;
rather than
Class myStringClass = MyString.class;
(But having used Java from day one, I didn't really notice when Class became generic);
NOTE: I have accepted @oxbow_lakes as this makes sense to me, but it is clearly a very complicated area. I would urge all programmers to use the specific Class<MyString> rather than Class. And Class<?> is much safer than Class.
Answer
Raw Types and Unbounded Wildcards
None of the previous answers have really addressed why you should prefer Class<?> over Class, as on the face of it, the former seems to offer no more information than the latter.
The reason is that, the raw type, i.e. Class, prevents the compiler from making generic type checks. That is, if you use raw types, you subvert the type-system. For example:
public void foo(Class<String> c) { System.out.println(c); }
Can be called thusly (it will both compile and run):
Class r = Integer.class
foo(r); //THIS IS OK (BUT SHOULDN'T BE)
But not by:
Class<?> w = Integer.class
foo(w); //WILL NOT COMPILE (RIGHTLY SO!)
By always using the non-raw form, even when you must use ? because you cannot know what the type parameter is (or is bounded by), you allow the compiler to reason about the correctness of your program more fully than if you used raw types.
Why have Raw Types at all?
The Java Language Specification says:
The use of raw types is allowed only as a concession to compatibility of legacy code
You should always avoid them. The unbounded wildcard ? is probably best described elsewhere but essentially means "this is parameterized on some type, but I do not know (or care) what it is". This is not the same as raw types, which are an abomination and do not exist in other languages with generics, like Scala.
Why is Class Parameterized?
Well, here is a use-case. Suppose I have some service interface:
public interface FooService
And I want to inject an implementation of it, using a system property to define the class to be used.
Class<?> c = Class.forName(System.getProperty("foo.service"));
I do not know at this point that my class, is of the correct type:
//next line throws ClassCastException if c is not of a compatible type
Class<? extends FooService> f = c.asSubclass(FooService.class);
Now I can instantiate a FooService:
FooService s = f.newInstance(); //no cast