Regular expression for email masking
I am trying to write a regular expression to mask an email address. Example below.
input: [email protected]
output: j*******@e*********.com
I have tried the following but I just can't seem to get it working correctly.
regex:
(?<=.).(?=[^@]\*?@)output:j*******@example.en.com
regex:
(?<=.).(?=[^@]\*?)(?=[^\.]\*?\.)output:j******************.com
Any help would be appreciated. demo
Answer
Update with various masking email solutions
[email protected]⇒f**@b**.com(current question) -s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*\\.)", "*")(see the regex demo)[email protected]⇒f**@b*r.com-s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*[^@]\\.)", "*")(see the regex demo)[email protected]⇒f*o@b*r.com-s.replaceAll("(?<=.)[^@](?=[^@]*?[^@]@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*[^@]\\.)", "*")(see the regex demo)[email protected]⇒f**@b*****m-s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?!$)", "*")(see the regex demo)[email protected]⇒f*o@b*****m-s.replaceAll("(?<=.)[^@](?=[^@]*[^@]@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?!$)", "*")(see the regex demo)
Original answer
In case you can't use a code-based solution, you may use
s.replaceAll("(?<=.)[^@](?=[^@]*?@)|(?:(?<=@.)|(?!^)\\G(?=[^@]*$)).(?=.*\\.)", "*")
See the regex demo
What it does:
(?<=.)[^@](?=[^@]*?@)-any char other than@([^@]) that is preceded by any single char ((?<=.)) and is followed with any 0 or more chars other than@up to a@((?=[^@]*?@))|- or(?:(?<=@.)|(?!^)\\G(?=[^@]*$))- match a location in the string that is preceded with@and any char ((?<=@.)) or (|) the end of the previous successful match ((?!^)\\G) that is followed with any 0+ chars other than@uo to the end of string ((?=[^@]*$)).- any single char(?=.*\\.)- followed with any 0+ chars up to the last.symbol in the string.