Show soft keyboard for dialog

Question

I am displaying a dialog with an edittext view. However, the softkeyboard will open only if the user presses inside the editview. So I tried calling an InputMethodManager with the following code.

InputMethodManager imm =
 (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
imm.showSoftInput(dialogField,0);

The dialogField is the input field. However, when exactly am I supposed to do this? I tried it in the onStart() method of the dialog, but nothing happens. I also tried requesting the focus for the dialogField before, but that changes nothing.

I also tried this code

dialogField.setOnFocusChangeListener(new View.OnFocusChangeListener()
{
    public void onFocusChange (View v, boolean hasFocus)
    {
        if (hasFocus)
        {
            Main.log("here");
            dialogInput.getWindow().setSoftInputMode(
              WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
            /*
                InputMethodManager mgr =
                  (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
                mgr.showSoftInput(dialogField,0);
            */
        }
    }
});

in both versions. But no soft keyboard would like to appear. The Main.log is just a log, which shows me that the function is actually called. And yes, it is called.

I could get the keyboard with the SHOW_FORCED flag before the dialog opens. But then it will not close on exit. And I can only do that BEFORE I show the dialog. Inside any callbacks it does not work either.

Answer 1

Awesome question, I was trying to do that too and found a solution.

Using the dialog builder class AlertDialog.Builder you will have to invoke the dialog like this:

AlertDialog.Builder builder = new AlertDialog.Builder();
AlertDialog dialog;

builder.set...

dialog = builder.create();
dialog.getWindow().setSoftInputMode(LayoutParams.SOFT_INPUT_STATE_VISIBLE);
dialog.show();

This worked fine for me.

Note: you must import android.view.WindowManager.LayoutParams; for the constant value there.