How do Java Interfaces simulate multiple inheritance?

jacknad picture jacknad · Aug 24, 2010 · Viewed 95.6k times · Source

I am reading "The Java Tutorial" (for the 2nd time). I just got through the section on Interfaces (again), but still do not understand how Java Interfaces simulate multiple inheritance. Is there a clearer explanation than what is in the book?

Answer

Peter Tillemans picture Peter Tillemans · Aug 24, 2010

Suppose you have 2 kinds of things in your domain : Trucks and Kitchens

Trucks have a driveTo() method and Kitchens a cook() method.

Now suppose Pauli decides to sell pizzas from the back of a delivery truck. He wants a thing where he can driveTo() and cook() with.

In C++ he would use multiple inheritance to do this.

In Java that was considered to be too dangerous so you can inherit from a main class, but you can "inherit" behaviors from interfaces, which are for all intents and purposes abstract classes with no fields or method implementations.

So in Java we tend to implement multiple inheritance using delegations :

Pauli subclasses a truck and adds a kitchen to the truck in a member variable called kitchen. He implements the Kitchen interface by calling kitchen.cook().

class PizzaTruck extends Truck implements Kitchen {
   Kitchen kitchen;

   public void cook(Food foodItem) {
      kitchen.cook(foodItem);
   }
}

He is a happy man because he can now do things like ;

pizzaTruck.driveTo(beach);
pizzaTruck.cook(pizzaWithExtraAnchovies);

Ok, this silly story was to make the point that it is no simulation of multiple inheritance, it is real multiple inheritance with the proviso that you can only inherit the contract, only inherit from empty abstract base classes which are called interfaces.

(update: with the coming of default methods interfaces now can also provide some behavior to be inherited)