The program finishes after nine prints:
class BeeperControl {
private final ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(1);
public void beep() {
final Runnable beeper = new Runnable() {
public void run() {
System.out.println("beep");
}
};
final ScheduledFuture<?> beeperHandle = scheduler.scheduleAtFixedRate(
beeper, 1, 1, SECONDS);
scheduler.schedule(new Runnable() {
public void run() {
beeperHandle.cancel(true);
}
}, 1 * 9, SECONDS);
}
public static void main(String[] args) {
BeeperControl bc = new BeeperControl();
bc.beep();
}
}
How to stop a process (i.e. java process in eclipse for example) because it does not stop after a time limit in 9 seconds?
The issue you have is that the scheduler keeps a live thread around after you have cancelled the beep task.
If there is a live non-daemon thread, the JVM stays alive.
The reason that it keeps this thread around is that you have told it to do so in this line:
private final ScheduledExecutorService scheduler
= Executors.newScheduledThreadPool(1);
Note the documentation of newScheduledThreadPool(int corePoolSize)
:
corePoolSize
- the number of threads to keep in the pool, even if they are idle.
So, you have two possible ways to cause the JVM to terminate:
Pass 0
to newScheduledThreadPool
instead of 1. The scheduler will not keep a live thread, and the JVM will terminate.
Shut down the scheduler. You are supposed to do so anyway to release its resources. So change the run
in your anonymous Runnable
to:
public void run() {
beeperHandle.cancel(true);
scheduler.shutdown();
}
(In fact, you don't need the cancel
there - the shutdown
will take effect as soon as the next "beep" is completed.)