Java: Anonymous inner class using a local variable

Alex Wayne picture Alex Wayne · Jul 15, 2010 · Viewed 10.6k times · Source

How can I get the value of userId passed to this method in my anonymous inner subclass here?

public void doStuff(String userID) {
    doOtherStuff(userID, new SuccessDelegate() {
        @Override
        public void onSuccess() {
            Log.e(TAG, "Called delegate!!!! "+ userID);
        }
    });
}

I get this error:

Cannot refer to a non-final variable userID inside an inner class defined in a different method

I'm pretty sure I can't assign it as final since it's a variable with an unknown value. I had heard that this syntax does preserve scope in some way, so I think there must be a syntax trick I don't quite know yet.

Answer

TofuBeer picture TofuBeer · Jul 15, 2010

As everyone else here has said, local variables have to be final to be accessed by an inner class.

Here is (basically) why that is... if you write the following code (long answer, but, at the bottom, you can get the short version :-):

class Main
{
    private static interface Foo
    {
        void bar();
    }

    public static void main(String[] args)
    {
        final int x;
        Foo foo;

        x = 42;
        foo = new Foo()
        {
            public void bar()
            {
                System.out.println(x);
            }
        };

        foo.bar();
    }
}

the compiler translates it roughly like this:

class Main
{
    private static interface Foo
    {
        void bar();
    }

    public static void main(String[] args)
    {
        final int x;
        Foo foo;

        x = 42;

        class $1
            implements Foo
        {
            public void bar()
            {
                System.out.println(x);
            }
        }

        foo = new $1();
        foo.bar();
    }
}

and then this:

class Main
{
    private static interface Foo
    {
        void bar();
    }

    public static void main(String[] args)
    {
        final int x;
        Foo foo;

        x = 42;
        foo = new $1(x);
        foo.bar();
    }

    private static class $1
        implements Foo
    {
        private final int x;

        $1(int val)
        {
           x = val;
        }

        public void bar()
        {
            System.out.println(x);
        }
    }
}

and finally to this:

class Main
{
    public static void main(String[] args) 
    {
        final int x;
        Main$Foo foo;

        x = 42;
        foo = new Main$1(x);
        foo.bar();
    }
}

interface Main$Foo
{
    void bar();
}

class Main$1
    implements Main$Foo
{
    private final int x;

    Main$1(int val)
    {
       x = val;
    }

    public void bar()
    {
        System.out.println(x);
    }
}

The important one is where it adds the constructor to $1. Imagine if you could do this:

class Main
{
    private static interface Foo
    {
        void bar();
    }

    public static void main(String[] args)
    {
        int x;
        Foo foo;

        x = 42;
        foo = new Foo()
        {
            public void bar()
            {
                System.out.println(x);
            }
        };

        x = 1;

        foo.bar();
    }
}

You would expect that foo.bar() would print out 1 but it would actually print out 42. By requiring local variables to be final this confusing situation cannot arise.