How to disable spring security for particular url

Prabjot Singh picture Prabjot Singh · May 21, 2015 · Viewed 145.2k times · Source

I am using stateless spring security,but in case of signup i want to disable spring security.I disabled using

antMatchers("/api/v1/signup").permitAll().

but it is not working,i am getting error below:

 message=An Authentication object was not found in the SecurityContext, type=org.springframework.security.authentication.AuthenticationCredentialsNotFoundException

I think this means spring security filters are working

My url's order always will be "/api/v1"

My spring config is

@Override
    protected void configure(HttpSecurity http) throws Exception {

         http.
         csrf().disable().
         sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS).
         and().
         authorizeRequests().
         antMatchers("/api/v1/signup").permitAll().
         anyRequest().authenticated().
         and().
         anonymous().disable();
        http.addFilterBefore(new AuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class);
    }

My authentication filter is

@Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        HttpServletRequest httpRequest = asHttp(request);
        HttpServletResponse httpResponse = asHttp(response);

        String username = httpRequest.getHeader("X-Auth-Username");
        String password = httpRequest.getHeader("X-Auth-Password");
        String token = httpRequest.getHeader("X-Auth-Token");

        String resourcePath = new UrlPathHelper().getPathWithinApplication(httpRequest);

        try {

            if (postToAuthenticate(httpRequest, resourcePath)) {            
                processUsernamePasswordAuthentication(httpResponse, username, password);
                return;
            }

            if(token != null){
                processTokenAuthentication(token);
            }
            chain.doFilter(request, response);
        } catch (InternalAuthenticationServiceException internalAuthenticationServiceException) {
            SecurityContextHolder.clearContext();
            logger.error("Internal authentication service exception", internalAuthenticationServiceException);
            httpResponse.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
        } catch (AuthenticationException authenticationException) {
            SecurityContextHolder.clearContext();
            httpResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED, authenticationException.getMessage());
        } finally {
        }
    }

     private HttpServletRequest asHttp(ServletRequest request) {
            return (HttpServletRequest) request;
        }

        private HttpServletResponse asHttp(ServletResponse response) {
            return (HttpServletResponse) response;
        }

        private boolean postToAuthenticate(HttpServletRequest httpRequest, String resourcePath) {
            return Constant.AUTHENTICATE_URL.equalsIgnoreCase(resourcePath) && httpRequest.getMethod().equals("POST");
        }

        private void processUsernamePasswordAuthentication(HttpServletResponse httpResponse,String username, String password) throws IOException {
            Authentication resultOfAuthentication = tryToAuthenticateWithUsernameAndPassword(username, password);
            SecurityContextHolder.getContext().setAuthentication(resultOfAuthentication);
            httpResponse.setStatus(HttpServletResponse.SC_OK);
            httpResponse.addHeader("Content-Type", "application/json");
            httpResponse.addHeader("X-Auth-Token", resultOfAuthentication.getDetails().toString());
        }

        private Authentication tryToAuthenticateWithUsernameAndPassword(String username,String password) {
            UsernamePasswordAuthenticationToken requestAuthentication = new UsernamePasswordAuthenticationToken(username, password);
            return tryToAuthenticate(requestAuthentication);
        }

        private void processTokenAuthentication(String token) {
            Authentication resultOfAuthentication = tryToAuthenticateWithToken(token);
            SecurityContextHolder.getContext().setAuthentication(resultOfAuthentication);
        }

        private Authentication tryToAuthenticateWithToken(String token) {
            PreAuthenticatedAuthenticationToken requestAuthentication = new PreAuthenticatedAuthenticationToken(token, null);
            return tryToAuthenticate(requestAuthentication);
        }

        private Authentication tryToAuthenticate(Authentication requestAuthentication) {
            Authentication responseAuthentication = authenticationManager.authenticate(requestAuthentication);
            if (responseAuthentication == null || !responseAuthentication.isAuthenticated()) {
                throw new InternalAuthenticationServiceException("Unable to authenticate Domain User for provided credentials");
            }
            logger.debug("User successfully authenticated");
            return responseAuthentication;
        }

My controller is

@RestController
public class UserController {

    @Autowired
    UserService userService;

    /**
     * to pass user info to service
     */
    @RequestMapping(value = "api/v1/signup",method = RequestMethod.POST)
    public String saveUser(@RequestBody User user) {
        userService.saveUser(user);
        return "User registerted successfully";
    }
}

I am totally new to spring,please help me how to do it ?

Answer

M. Deinum picture M. Deinum · May 21, 2015

When using permitAll it means every authenticated user, however you disabled anonymous access so that won't work.

What you want is to ignore certain URLs for this override the configure method that takes WebSecurity object and ignore the pattern.

@Override
public void configure(WebSecurity web) throws Exception {
    web.ignoring().antMatchers("/api/v1/signup");
}

And remove that line from the HttpSecurity part. This will tell Spring Security to ignore this URL and don't apply any filters to them.