I was wondering if it is possible to find the closest element in a List
for a element that is not there.
For example if we had the values [1,3,6,7] and we are looking for the element closest to 4, it should return 3, because 3 is the biggest number in the array, that is smaller than 4.
I hope it makes sense, because English is not my native language.
If the array is sorted you can do a modified binary search in O( log n )
:
public static int search(int value, int[] a) {
if(value < a[0]) {
return a[0];
}
if(value > a[a.length-1]) {
return a[a.length-1];
}
int lo = 0;
int hi = a.length - 1;
while (lo <= hi) {
int mid = (hi + lo) / 2;
if (value < a[mid]) {
hi = mid - 1;
} else if (value > a[mid]) {
lo = mid + 1;
} else {
return a[mid];
}
}
// lo == hi + 1
return (a[lo] - value) < (value - a[hi]) ? a[lo] : a[hi];
}