I have a class defined as follows:
public class Person {
private String name;
// constructor and getter/setter omitted
}
I tried to print an instance of my class:
System.out.println(myPerson);
but I got the following output: com.foo.Person@2f92e0f4
.
A similar thing happened when I tried to print an array of Person
objects:
Person[] people = //...
System.out.println(people);
I got the output: [Lcom.foo.Person;@28a418fc
What does this output mean? How do I change this output so it contains the name of my person? And how do I print collections of my objects?
Note: this is intended as a canonical Q&A about this subject.
All Java objects have a toString()
method, which is invoked when you try and print the object.
System.out.println(myObject); // invokes myObject.toString()
This method is defined in the Object
class (the superclass of all Java objects). The Object.toString()
method returns a fairly ugly looking string, composed of the name of the class, an @
symbol and the hashcode of the object in hexadecimal. The code for this looks like:
// Code of Object.toString()
public String toString() {
return getClass().getName() + "@" + Integer.toHexString(hashCode());
}
A result such as com.foo.MyType@2f92e0f4
can therefore be explained as:
com.foo.MyType
- the name of the class, i.e. the class is MyType
in the package com.foo
.@
- joins the string together2f92e0f4
the hashcode of the object.The name of array classes look a little different, which is explained well in the Javadocs for Class.getName()
. For instance, [Ljava.lang.String
means:
[
- an single-dimensional array (as opposed to [[
or [[[
etc.)L
- the array contains a class or interfacejava.lang.String
- the type of objects in the arrayTo print something different when you call System.out.println(myObject)
, you must override the toString()
method in your own class. Here's a simple example:
public class Person {
private String name;
// constructors and other methods omitted
@Override
public String toString() {
return name;
}
}
Now if we print a Person
, we see their name rather than com.foo.Person@12345678
.
Bear in mind that toString()
is just one way for an object to be converted to a string. Typically this output should fully describe your object in a clear and concise manner. A better toString()
for our Person
class might be:
@Override
public String toString() {
return getClass().getSimpleName() + "[name=" + name + "]";
}
Which would print, e.g., Person[name=Henry]
. That's a really useful piece of data for debugging/testing.
If you want to focus on just one aspect of your object or include a lot of jazzy formatting, you might be better to define a separate method instead, e.g. String toElegantReport() {...}
.
Many IDEs offer support for auto-generating a toString()
method, based on the fields in the class. See docs for Eclipse and IntelliJ, for example.
Several popular Java libraries offer this feature as well. Some examples include:
@ToString
annotation from Project Lombok
So you've created a nice toString()
for your class. What happens if that class is placed into an array or a collection?
If you have an array of objects, you can call Arrays.toString()
to produce a simple representation of the contents of the array. For instance, consider this array of Person
objects:
Person[] people = { new Person("Fred"), new Person("Mike") };
System.out.println(Arrays.toString(people));
// Prints: [Fred, Mike]
Note: this is a call to a static method called toString()
in the Arrays class, which is different to what we've been discussing above.
If you have a multi-dimensional array, you can use Arrays.deepToString()
to achieve the same sort of output.
Most collections will produce a pretty output based on calling .toString()
on every element.
List<Person> people = new ArrayList<>();
people.add(new Person("Alice"));
people.add(new Person("Bob"));
System.out.println(people);
// Prints [Alice, Bob]
So you just need to ensure your list elements define a nice toString()
as discussed above.