Getting java.lang.ClassCastException: android.os.BinderProxy every time i declare and run two services

Prathmesh Swaroop picture Prathmesh Swaroop · Feb 6, 2015 · Viewed 10.4k times · Source

I am encountering following binder.proxy exception every time i declare and run two services. One service runs in different Process(Private to app) and another service runs in same process as My Application is running in(Default App Process) with a Binder Implementation.

AndroidManifest.xml:

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.service.check"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk
        android:minSdkVersion="8"
        android:targetSdkVersion="21" />

    <application
        android:name="com.service.check.MainApplication"
        android:allowBackup="true"
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >
        <activity
            android:name=".MainActivity"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>

         <service
            android:name="com.service.check.SecondService"
            android:exported="false"/>

        <service
            android:name="com.service.check.FirstService"
            android:process=":newProcess" >
        </service>
    </application>

</manifest>

I am launching my first service in MainActivity on Button click as:

MainActivity.java

public class MainActivity extends ActionBarActivity implements OnClickListener {

    private Button mLanchServiceBtn;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        mLanchServiceBtn=(Button) findViewById(R.id.launch_btn);

        mLanchServiceBtn.setOnClickListener(this);
    }
    @Override
    public void onClick(View v) {
       //Starting first service
        Intent launch=new Intent(this,FirstService.class);
        startService(launch);

    }
}

And second service in MainApplication class as.

MainApplication.java

    public class MainApplication extends Application {

        private SecondService.LocalBinder mBinder;
        private ServiceConnection mConnection = new ServiceConnection() {

            @Override
            public void onServiceConnected(ComponentName className, IBinder service) {
                mBinder = (LocalBinder) service;
            }

            @Override
            public void onServiceDisconnected(ComponentName arg0) {
            }
        };

        @Override
        public void onCreate() {
            super.onCreate();

            //starting second service               
            Intent launch=new Intent(this,SecondService.class);
            startService(launch);

            //Binding to it 
            bindService(launch, mConnection, BIND_AUTO_CREATE);
        }

    }

FirstService.java

public class FirstService extends Service {
    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }
}

SecondService.java

public class SecondService extends Service{

    //Service Containing Local Binder
    private LocalBinder mBinder=new LocalBinder();
    @Override
    public IBinder onBind(Intent intent) {
        return mBinder;
    }
    class LocalBinder extends Binder{

        public LocalBinder() {
        }
    }
}

StackTrace:

 02-05 10:32:25.035: E/AndroidRuntime(1424): Process:

 com.service.check:newProcess, PID: 1424 02-05 10:32:25.035:
 E/AndroidRuntime(1424): java.lang.ClassCastException:
 android.os.BinderProxy cannot be cast to
 com.service.check.SecondService$LocalBinder 02-05 10:32:25.035:
 E/AndroidRuntime(1424):    at
 com.service.check.MainApplication$1.onServiceConnected(MainApplication.java:23)
 02-05 10:32:25.035: E/AndroidRuntime(1424):    at
 android.app.LoadedApk$ServiceDispatcher.doConnected(LoadedApk.java:1101)

I have referred the following links to sort out the issue which says, if my activity and service are in separate processes then we should not bind the way I have done.

Android service android.os.BinderProxy error

java.lang.ClassCastException: android.os.BinderProxy cannot be cast to LocalBinder

But in my case: I am binding to SecondService from MainApplication and both are running in same Process(i.e Default Application Process). Still I am facing binderProxy exception in SecondService , And my FirstService runs in separate process which I am not even binding to.

Please help me out with this situation and, Suggest me a best possible way so that I can implement same scenario without any crash.

Answer

Coeffect picture Coeffect · Jun 5, 2015

Ran into this issue (local service returning a BinderProxy), wanted to post what I'd found since I found this page while trying to debug. The short version as a run on sentence: starting a remote service creates a second instance of your Application class in a new process which then tries to bind to the local service that was started by the original Application instance as if it was a local service but since the service is running in the original process it's binding across processes and you get a BinderProxy instead of your expected Binder class.

There's a few things to keep in mind about Android services. Every service has an assigned process it will run in. If you don't assign a process in your Android Manifest it will run in the default process (the process where the Application, Activities, etc are run). Not giving a process name doesn't mean that it will run the service in the same process that you're binding to/starting the service from.

Let's say I have a MyApplication class which attempts to bind to two services on start up: one service running in the default process (we'll call this the LocalService), one running in a separate process (the RemoteService).

The user launches my app which creates a MyApplication instance in the default process. This instance then tries to bind to the LocalService. Android creates the LocalService in the default process and returns the LocalService's Binder class to the app (mBinder = (LocalBinder) service;). That's all good, we've successfully bound to the LocalService.

Next the app tries to bind to the RemoteService. Android creates a new process with the name you've supplied in the Android Manifest. However, before it can create the RemoteService it needs to create an Application for the service to run in. It creates a new MyApplication instance in the remote process and starts that up.

However, that new MyApplication instance running in a separate process tries to bind to the LocalService during start up. Because the LocalService is running in the default process this is a cross process binding but MyApplication expects this to be an in process binding. Android returns a BinderProxy, the second MyApplication instance tries to cast it to a LocalBinder and crashes. The fun part is that it crashes in a different process so your app and activity can actually continue running. You'll just never be able to bind to the remote service.

If you want to bind to a local service with an Application context and also use a remote service you'll need to handle the fact that Android will create another Application in the remote process when starting the remote service. I haven't bothered to try this (I just made my remote service a local service), but you could probably check the process name during the application's on create and not bind if it's not the default process.