In the JSON Response String contains auto-added Backslashes

Jahanzeb Khan picture Jahanzeb Khan · Dec 20, 2014 · Viewed 11.6k times · Source

I am calling a webservice to get a JSON string response and It contains backslashes which is not in original string. Below is my code for requesting a JSON string object which is: {"name":"Name","id":1}

protected String doInBackground(String... uri) 
    {
        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response;
        String responseString = null;
        try {
            response = httpclient.execute(new HttpGet(uri[0]));
            StatusLine statusLine = response.getStatusLine();
            if(statusLine.getStatusCode() == HttpStatus.SC_OK){
                ByteArrayOutputStream out = new ByteArrayOutputStream();
                response.getEntity().writeTo(out);
                out.close();
                responseString = out.toString();
            } else{
                //Closes the connection.
                response.getEntity().getContent().close();
                throw new IOException(statusLine.getReasonPhrase());
            }
        } catch (ClientProtocolException e) {
            //TODO Handle problems..
        } catch (IOException e) {
            //TODO Handle problems..
        }
        return responseString;
    }

In post execute I just try to parse this respose string into JSONObject. code is bellow:

protected void onPostExecute(String result) {
        super.onPostExecute(result);
        TextView t1=(TextView)findViewById(R.id.textView1);
        TextView t2=(TextView)findViewById(R.id.textView2);       

        //String s = result.replaceAll("\\", ""); //I have tried to escape backslashes also using this line.
        String name="failure";
        int id;
        try 
        {
            t1.setText(result);
            JSONObject reader = new JSONObject(result.toString()); //Exception on this line.
            //name = reader.getString("name").toString();
            //id = reader.getInt("id");             
            t2.setText(name);
        } 
        catch (Exception e) 
        {
            t2.setText(e.toString());
        }
    }

Rsponse string is: "{\"name\":\"Name\",\"id\":1}" And when I try to parse it to JSONObject it throws an exception says: org.json.JSONException value "{"name":"Name","id":1}" type cannot converted into json object.

Answer

Kanwarbir Singh picture Kanwarbir Singh · Apr 18, 2016

I know this is an old question, but I got stuck with the same problem , the only difference that, I had a JSONArray instead of a JSONObject . But the method I followed for my problem after scouring Stackoverflow for similar questions was the one I am going to state below, in case anyone comes looking for an answer just as I stumbled across your question.

First of all,you need to study the json response you receive. "{\"name\":\"Name\",\"id\":1}" is a String. You see the " before { and after }. If this string is the raw json you receive from your web service,then your method to escape the backslashes and then building a JSONObject out of that string ought to have worked. One method you could try is :

result = result.trim();
result = result.substring(1,result.length() - 1);
result = result.replace("\\","");

Then,

JSONObject reader = new JSONObject(result);
name = reader.getString("name");
id = reader.getInt("id"); 

The mantra for this solution was to get rid of those extra inverted commas before the json response and then creating a JSONObject from that string.

As for my situation regarding a JSONArray,the solution was as below:

Json response : {"error":false,"myorderdetails":{"order_id":"26","orderjson":"[{\"Name\":\"Disprin\",\"Id\":53,\"Quantity\":1,\"Price\":50}]"}}

JSONObject jObj = new JSONObject(response);
boolean error = jObj.getBoolean("error");
if (!error)
{
    JSONObject jsonObj= jObj.getJSONObject("myorderdetails");
    String s = jsonObj.getString("orderjson");
    s = s.replace("\\", "");
    JSONArray orderjson = new JSONArray(s);

    for(int i=0;i<orderjson.length();i++){
    JSONObject jsonObject=orderjson.getJSONObject(i);
    String pname = (String)jsonObject.get("Name");
    int pquantity = jsonObject.getInt("Quantity");
    double pprice = jsonObject.getDouble("Price");
}