I can't make heads or tails of the following code from "java puzzlers" by joshua bloch.
public class Test22{
public static void main(String args[]){
int j=0;
for(int i=0;i<100;i++){
j=j++;
}
System.out.println(j); //prints 0
int a=0,b=0;
a=b++;
System.out.println(a);
System.out.println(b); //prints 1
}
}
I can't get the part where j prints 0. According to the author,
j=j++
is similar to
temp=j;
j=j+1;
j=temp;
But
a=b++
makes b 1. So it should've evaluated like this,
a=b
b=b+1
By following the same logic, shouldn't
j=j++
be evaluated as,
j=j
j=j+1
Where does the temp come into picture here? Any explanations would be much appreciated. << I'm breaking my head over this. ;)>> Thanks in advance.
Let's break down your own argument:
According to the author,
j=j++;
is similar to
temp=j; j=j+1; // increment j=temp; // then assign
Yes, you're right so far..., but here's where you got it wrong:
But
a=b++;
makes
b=1
. So it should've evaluated like this,a=b; // assign b=b+1; // then increment
WRONG! You're not applying the rule consistently! You've changed the order from increment then assign to assign then increment!!! It's actually evaluated like this:
temp=b;
b=b+1; // increment
a=temp; // then assign
Basically assignments of this form:
lhs = rhs++;
is similar to doing something like this:
temp = rhs;
rhs = rhs+1; // increment
lhs = temp; // then assign
Apply this to a = b++;
. Then apply it also to j = j++;
. That's why you get the results that you get.
What you did was you came up with your own interpretation of what a = b++;
does -- a WRONG interpretation that doesn't follow the above rule. That's the source of your confusion.
"...the value 1 is added to the value of the variable and the sum is stored back into the variable [...] The value of the postfix increment expression is the value of the variable before the new value is stored."