Java: custom-exception-error

Question

$ javac TestExceptions.java 
TestExceptions.java:11: cannot find symbol
symbol  : class test
location: class TestExceptions
            throw new TestExceptions.test("If you see me, exceptions work!");
                                    ^
1 error

Code

import java.util.*;
import java.io.*;

public class TestExceptions {
    static void test(String message) throws java.lang.Error{
        System.out.println(message);
    }   

    public static void main(String[] args){
        try {
             // Why does it not access TestExceptions.test-method in the class?
            throw new TestExceptions.test("If you see me, exceptions work!");
        }catch(java.lang.Error a){
            System.out.println("Working Status: " + a.getMessage() );
        }
    }
}

Answer 1

TestExceptions.test returns type void, so you cannot throw it. For this to work, it needs to return an object of a type that extends Throwable.

One example might be:

   static Exception test(String message) {
        return new Exception(message);
    } 

However, this isn't very clean. A better pattern would be to define a TestException class that extends Exception or RuntimeException or Throwable, and then just throw that.

class TestException extends Exception {
   public TestException(String message) {
     super(message);
   }
}

// somewhere else
public static void main(String[] args) throws TestException{
    try {
        throw new TestException("If you see me, exceptions work!");
    }catch(Exception a){
        System.out.println("Working Status: " + a.getMessage() );
    }
}

(Also note that all classes in package java.lang can be referenced by their class name rather than their fully-qualified name. That is, you don't need to write java.lang.)