Spring cron expression for every day 1:01:am

Question

I'm trying to have my code execute on a fixed schedule, based on a Spring cron expression. I would like the code to be executed every day at 1:01:am. I tried the following expression, but this didn't fire up for me. What's wrong with the syntax here?

@Scheduled(cron = "0 1 1 ? * *")
public void resetCache() {
    // ...
}

Answer 1

Try with:

@Scheduled(cron = "0 1 1 * * ?")

Below you can find the example patterns from the spring forum:

* "0 0 * * * *" = the top of every hour of every day.
* "*/10 * * * * *" = every ten seconds.
* "0 0 8-10 * * *" = 8, 9 and 10 o'clock of every day.
* "0 0 8,10 * * *" = 8 and 10 o'clock of every day.
* "0 0/30 8-10 * * *" = 8:00, 8:30, 9:00, 9:30 and 10 o'clock every day.
* "0 0 9-17 * * MON-FRI" = on the hour nine-to-five weekdays
* "0 0 0 25 12 ?" = every Christmas Day at midnight

Cron expression is represented by six fields:

second, minute, hour, day of month, month, day(s) of week

(*) means match any

*/X means "every X"

? ("no specific value") - useful when you need to specify something in one of the two fields in which the character is allowed, but not the other. For example, if I want my trigger to fire on a particular day of the month (say, the 10th), but I don't care what day of the week that happens to be, I would put "10" in the day-of-month field and "?" in the day-of-week field.

PS: In order to make it work, remember to enable it in your application context: https://docs.spring.io/spring/docs/3.2.x/spring-framework-reference/html/scheduling.html#scheduling-annotation-support