How can I create a simple docx file with Apache POI?

guerda picture guerda · Apr 7, 2010 · Viewed 31.5k times · Source

I'm searching for a simple example code or a complete tutorial how to create a docx file with Apache POI and its underlying openxml4j.

I tried the following code (with a lot of help from the Content Assist, thanks Eclipse!) but the code does not work correctly.

String tmpPathname = aFilename + ".docx";
File tmpFile = new File(tmpPathname);

ZipPackage tmpPackage = (ZipPackage) OPCPackage.create(tmpPathname);
PackagePartName tmpFirstPartName = PackagingURIHelper.createPartName("/FirstPart");
PackagePart tmpFirstPart = tmpPackage.createPart(tmpFirstPartName, "ISO-8859-1");

XWPFDocument tmpDocument = new XWPFDocument(tmpPackage); //Exception
XWPFParagraph tmpParagraph = tmpDocument.createParagraph();
XWPFRun tmpRun = tmpParagraph.createRun();
tmpRun.setText("LALALALAALALAAAA");
tmpRun.setFontSize(18);
tmpPackage.save(tmpFile);

The thrown exception is the following:

Exception in thread "main" java.lang.NullPointerException
    at org.apache.poi.POIXMLDocumentPart.read(POIXMLDocumentPart.java:235)
    at org.apache.poi.POIXMLDocument.load(POIXMLDocument.java:196)
    at org.apache.poi.xwpf.usermodel.XWPFDocument.<init>(XWPFDocument.java:94)
    at DocGenerator.makeDocxWithPoi(DocGenerator.java:64)
    at DocGenerator.main(DocGenerator.java:50)

Does anybody can help me with my (really simple) requirements?

Answer

Valentin Rocher picture Valentin Rocher · Apr 7, 2010

Here is how you can create a simple docx file with POI :

XWPFDocument document = new XWPFDocument();
XWPFParagraph tmpParagraph = document.createParagraph();
XWPFRun tmpRun = tmpParagraph.createRun();
tmpRun.setText("LALALALAALALAAAA");
tmpRun.setFontSize(18);
document.write(new FileOutputStream(new File("yourpathhere")));
document.close();