java.lang.IllegalArgumentException: protocol = http host = null

java url apache-tika
Goko Gorgiovski picture Goko Gorgiovski · Sep 3, 2014 · Viewed 26.1k times · Source

For this link http://bits.blogs.nytimes.com/2014/09/02/uber-banned-across-germany-by-frankfurt-court/?partner=rss&emc=rss this code doesn`t work but if I put another for exemple: https://www.google.com everything is ok:

    URL url = new URL("http://bits.blogs.nytimes.com/2014/09/02/uber-banned-across-germany-by-frankfurt-court/?partner=rss&emc=rss");
        URLConnection uc;
    uc = url.openConnection();
    uc.setRequestProperty("User-Agent", "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_7; en-US) AppleWebKit/534.16 (KHTML, like Gecko) Chrome/10.0.648.205 Safari/534.16");
    uc.addRequestProperty("referer", "http://www.facebook.com");
    uc.connect();     

    this.input = uc.getInputStream();

I get this exception:

java.lang.IllegalArgumentException: protocol = http host = null
    at sun.net.spi.DefaultProxySelector.select(DefaultProxySelector.java:170)
    at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:926)
    at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:850)
    at sun.net.www.protocol.http.HttpURLConnection.followRedirect(HttpURLConnection.java:2398)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1557)
    at UrlParser.<init>(UrlParser.java:48)
    at TikaParser.test_url_parser(TikaParser.java:186)
    at TikaParser.run(TikaParser.java:256)
    at java.lang.Thread.run(Thread.java:745)

what is wrong with my code?

Answer

wsams picture wsams · Feb 14, 2015

I encountered this same exception when the URL started with http:/ instead of http://. e.g. http:/www.example.com

This was in the org.springframework.web.client.RestTemplate.exchange() method, so it's not quite the same context, but maybe a similar issue.

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