java.lang.String cannot be cast to org.json.simple.JSONObject simple-json

Roshan Wijesena picture Roshan Wijesena · Aug 29, 2014 · Viewed 48.3k times · Source

I am getting strange problem while trying to parse a simple json using simple-json by google.

Here is my code which is not working:

String s = args[0].toString();
JSONObject json = (JSONObject)new JSONParser().parse(s);

When I execute, it will give me the exception java.lang.String cannot be cast to org.json.simple.JSONObject

But when I hard code json directly like below its working fine. Wat could be the reason?

JSONObject json = (JSONObject)new JSONParser().parse("{\"application\":\"admin\",\"keytype\":\"PRODUCTION\",\"callbackUrl\":\"qwerewqr;ewqrwerq;qwerqwerq\",\"authorizedDomains\":\"ALL\",\"validityTime\":\"3600000\",\"retryAfterFailure\":true}");

UPDATE

When I print s, it will give me the output below:

"{\"application\":\"admin\",\"keytype\":\"PRODUCTION\",\"callbackUrl\":\"qwerewqr;ewqrwerq;qwerqwerq\",\"authorizedDomains\":\"ALL\",\"validityTime\":\"3600000\",\"retryAfterFailure\":true}"

Answer

Ankur Singhal picture Ankur Singhal · Aug 29, 2014

I ran this through eclipse by providing arguments in run configuration.

 public static void main(String[] args) {
        String s = args[0].toString();
        System.out.println("=>" + s);
        try {
            JSONObject json = (JSONObject) new JSONParser().parse(s);
            System.out.println(json);
        } catch (ParseException e) {
            e.printStackTrace();
        }
    }

Output

=>{"application":"admin","keytype":"PRODUCTION","callbackUrl":"qwerewqr;ewqrwerq;qwerqwerq","authorizedDomains":"ALL","validityTime":"3600000","retryAfterFailure":true}


{"validityTime":"3600000","callbackUrl":"qwerewqr;ewqrwerq;qwerqwerq","application":"admin","retryAfterFailure":true,"authorizedDomains":"ALL","keytype":"PRODUCTION"}