JTable Set Cell Color At Specific Value

Xerath picture Xerath · Aug 1, 2014 · Viewed 20.7k times · Source

I'm trying to write a method which for given parameters (value, color), sets color on the background of a cell which has value equal to cellValue.

What my method actually does is, it sets color on the background of a cells for whole row and when I select the row on the table, and I want method to only set color at specific column (where cellValue is equal to value) each time I call the method.

    void setCellBackgroundColor(boolean cellValue, final Color color) {
        List<List<Object>> data = tView.getTTableModel().getData();

        for (int row = 0; row < data.size(); row++) {
            for (int col = 0; col < data.get(row).size(); col++) {
                TableCellRenderer renderer = tView.table.getCellRenderer(row, Col);
                Component component = tView.table.prepareRenderer(renderer, row, col);
                boolean bValue = 
                    TDataTypeRenderer.parseIntoRealValue(
                        data.get(row).get(col)
                    )
                );
                if (bValue == cellValue) {
                    component.setBackground(color);
                }
    }

Answer

Braj picture Braj · Aug 1, 2014

when I select the row on the table, and I want method to only set color at specific column

Try with overridden prepareRenderer() method as suggested by @mKorbel.

sample code:

Object[] columnNames = { "A", "B", "C", "D" };
Object[][] data = { 
        { "abc", new Double(850.503), 53, true },
        { "lmn", new Double(36.23254), 6, false }, 
        { "pqr", new Double(8.3), 7, false },
        { "xyz", new Double(246.0943), 23, true } };

JTable table = new JTable(data, columnNames) {
    @Override
    public Component prepareRenderer(TableCellRenderer renderer, int row, int col) {
        Component comp = super.prepareRenderer(renderer, row, col);
        Object value = getModel().getValueAt(row, col);
        if (getSelectedRow() == row) {
            if (value.equals(false)) {
                comp.setBackground(Color.red);
            } else if (value.equals(true)) {
                comp.setBackground(Color.green);
            } else {
                comp.setBackground(Color.white);
            }
        } else {
            comp.setBackground(Color.white);
        }
        return comp;
    }
};

When selected first row:

enter image description here

When selected second row.

enter image description here

Read more...


EDIT

As per your last comment

Is it possible to change color with out clicking (selecting) row on the table?

Yes just remove the check of selected row.

    Object value = getModel().getValueAt(row, col);
    if (value.equals(false)) {
        comp.setBackground(Color.red);
    } else if (value.equals(true)) {
        comp.setBackground(Color.green);
    } else {
       comp.setBackground(Color.white);
    }

enter image description here