I have a string encoded in Base64:
eJx9xEERACAIBMBKJyKDcTzR_hEsgOxjAcBQFVVNvi3qEsrRnWXwbhHOmzWnctPHPVkPu-4vBQ==
How can I decode it in Scala language?
I tried to use:
val bytes1 = new sun.misc.BASE64Decoder().decodeBuffer(compressed_code_string)
But when I compare the byte array with the correct one that I generated in Python language, there is an error. Here is the command I used in python:
import base64
base64.urlsafe_b64decode(compressed_code_string)
The Byte Array in Scala is:
(120, -100, 125, -60, 65, 17, 0, 32, 8, 4, -64, 74, 39, 34, -125, 113, 60, -47, -2, 17, 44, -128, -20, 99, 1, -64, 80, 21, 85, 77, -66, 45, -22, 18, -54, -47, -99, 101, -16, 110, 17, -50, -101, 53, -89, 114, -45, -57, 61, 89, 15, -69, -2, 47, 5)
And the one generated in python is:
(120, -100, 125, -60, 65, 17, 0, 32, 8, 4, -64, 74, 39, 34, -125, 113, 60, -47, -2, 17, 44, -128, -20, 99, 1, -64, 80, 21, 85, 77, -66, 45, -22, 18, -54, -47, -99, 101, -16, 110, 17, -50, -101, 53, -89, 114, -45, -57, 61, 89, 15, -69, -18, 47, 5)
Note that there is a single difference in the end of the array
In Scala, Encoding a String to Base64 and decoding back to the original String using Java APIs:
import java.util.Base64
import java.nio.charset.StandardCharsets
scala> val bytes = "foo".getBytes(StandardCharsets.UTF_8)
bytes: Array[Byte] = Array(102, 111, 111)
scala> val encoded = Base64.getEncoder().encodeToString(bytes)
encoded: String = Zm9v
scala> val decoded = Base64.getDecoder().decode(encoded)
decoded: Array[Byte] = Array(102, 111, 111)
scala> val str = new String(bytes, StandardCharsets.UTF_8)
str: String = foo