I'm using Ebean with the Play 2 Framework and got two models: a user model and a book model. The user model is connected with the book model in a OneToMany Relationship. So every user can have many books or no book at all. The book model itself has properties too. Now I want to create a query in the user model, which returns only users, who have books with certain properties. For example: One property might be condition, like new or used. Now give me all users which have books in new condition. Is it possible to create such a query with the Ebean methods? Or do I have to use raw SQL?
Say you have the following models:
@Entity
public class User extends Model {
@Id
@Column(name = "user_index")
private int id;
@Column(name = "user_first_name")
private String firstName;
[...]
@OneToMany(mappedBy = "book_owner_index")
private List<Book> books;
public static Finder<Integer, User> find = new Finder<Integer, User>(Integer.class, User.class);
[...]
}
and
@Entity
public class Book extends Model {
@Id
@Column(name = "book_index")
private int id;
@Column(name = "book_name")
private String name;
@Column(name = "book_condition")
private String condition;
[...]
@ManyToOne
@JoinColumn(name = "book_owner_index", referencedColumnName = "user_index")
private User owner;
[...]
}
Then you can do a search like:
List<User> users = User.find.select("*")
.fetch("books")
.where()
.eq("books.condition", "new")
.findList();