I managed to create simple Websocket application with Spring 4 and Stomp. See my last question here Then I tried to use remote message broker(ActiveMQ). I just started the broker and changed
registry.enableSimpleBroker("/topic");
to
registry.enableStompBrokerRelay("/topic");
and it worked.
The question is how the broker is configured? I understand that in this case the application automagicaly finds the broker on localhost:defaultport, bu what if I need to point the app to some other broker on other machine?
The enableStompBrokerRelay
method returns a convenient Registration instance that exposes a fluent API.
You can use this fluent API to configure your Broker relay:
registry.enableStompBrokerRelay("/topic").setRelayHost("host").setRelayPort("1234");
You can also configure various properties, like login/pass credentials for your broker, etc.
Same with XML Configuration:
<websocket:message-broker>
<websocket:stomp-endpoint path="/foo">
<websocket:handshake-handler ref="myHandler"/>
<websocket:sockjs/>
</websocket:stomp-endpoint>
<websocket:stomp-broker-relay prefix="/topic,/queue"
relay-host="relayhost" relay-port="1234"
client-login="clientlogin" client-passcode="clientpass"
system-login="syslogin" system-passcode="syspass"
heartbeat-send-interval="5000" heartbeat-receive-interval="5000"
virtual-host="example.org"/>
</websocket:message-broker>
See the StompBrokerRelayRegistration javadoc for more details on properties and default values.