I'm doing some simple HTTP authentication and am getting a
java.lang.IllegalArgumentException: Illegal character(s) in message header value: Basic OGU0ZTc5ODBk(...trimmed from 76 chars...)
(...more password data...)
which I think is due to me having a really long username and password and the encoder wraps it with a \n
at 76 chars. Is there any way I can get around this? The URL only supports HTTP Basic Auth.
Here is my code:
private class UserPassAuthenticator extends Authenticator {
String user;
String pass;
public UserPassAuthenticator(String user, String pass) {
this.user = user;
this.pass = pass;
}
// This method is called when a password-protected URL is accessed
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication(user, pass.toCharArray());
}
}
private String fetch(StoreAccount account, String path) throws IOException {
Authenticator.setDefault(new UserPassAuthenticator(account.getCredentials().getLogin(), account.getCredentials().getPassword()));
URL url = new URL("https", account.getStoreUrl().replace("http://", ""), path);
System.out.println(url);
URLConnection urlConn = url.openConnection();
Object o = urlConn.getContent();
if (!(o instanceof String))
throw new IOException("Wrong Content-Type on " + url.toString());
// Remove the authenticator back to the default
Authenticator.setDefault(null);
return (String) o;
}
That seems to be a bug in Java.
Have you tried using alternative HTTP clients, such as the library from Apache?
Or instead of using the Authenticator, manually setting the header?
URL url = new URL("http://www.example.com/");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("Authorization", "Basic OGU0ZTc5ODBkABcde....");
The token value is encodeBase64("username:password").