I am trying to create a constructor that takes a field as a parameter, then puts it in a field that is stored in a superclass. Here is the code I am using
public crisps(String flavour, int quantity) {
this.flavour = super.getFlavour();
this.quantity = quantity;
}
In the superclass I have initialised the field with
private String flavour;
and I have an accessor method
public String getFlavour() {
return flavour;
}
I am getting an error "flavour has private access in the superclass", but I believe this shouldn't matter as I am calling the accessor method that returns it to the field?
What you should do:
Add a constructor to your super class:
public Superclass {
public SuperClass(String flavour) {
// super class constructor
this.flavour = flavour;
}
}
In the Crisps class:
public Crisps(String flavour, int quantity) {
super(flavour); // send flavour to the super class constructor
this.quantity = quantity;
}
Comments
Some comments to your question:
"In the superclass I have initialised the field with "
private String flavour;
This is not an initialization, it is a declaration. An initialization is when you set a value.
"I am getting an error " flavour has private access in the superclass" but I believe this shouldn't matter as I am calling the accessor method that returns it to the field?"
When you call a accessor (aka getter), it is ok - depends on the getter visibility. The problem in you code is the:
this.flavour =
because flavour is not a field declared on Crisps class, but on the supper class, so you can't do a direct access like that. you should use my suggestion or declare a setter on the super class:
public void setFlavour(String flavour) {
this.flavour = flavour;
}
Then you can use it on the child class:
public Crisps(String flavour, int quantity) {
this.quantity = quantity;
super.setFlavour(flavour);
}