How to asynchronously call a method in Java

Felipe Hummel picture Felipe Hummel · Dec 3, 2009 · Viewed 286k times · Source

I've been looking at Go's goroutines lately and thought it would be nice to have something similar in Java. As far as I've searched the common way to parallelize a method call is to do something like:

final String x = "somethingelse";
new Thread(new Runnable() {
           public void run() {
                x.matches("something");             
    }
}).start();

Thats not very elegant. Is there a better way of doing this? I needed such a solution in a project so I decided to implement my own wrapper class around a async method call.

I published my wrapper class in J-Go. But I don't know if it is a good solution. The usage is simple:

SampleClass obj = ...
FutureResult<Integer> res = ...
Go go = new Go(obj);
go.callLater(res, "intReturningMethod", 10);         //10 is a Integer method parameter
//... Do something else
//...
System.out.println("Result: "+res.get());           //Blocks until intReturningMethod returns

or less verbose:

Go.with(obj).callLater("myRandomMethod");
//... Go away
if (Go.lastResult().isReady())                //Blocks until myRandomMethod has ended
    System.out.println("Method is finished!");

Internally I'm using a class that implements Runnable and do some Reflection work to get the correct method object and invoking it.

I want some opinion about my tiny library and on the subject of making async method calls like this in Java. Is it safe? Is there already a simplier way?

Answer

AegisHexad picture AegisHexad · Jun 8, 2014

I just discovered that there is a cleaner way to do your

new Thread(new Runnable() {
    public void run() {
        //Do whatever
    }
}).start();

(At least in Java 8), you can use a lambda expression to shorten it to:

new Thread(() -> {
    //Do whatever
}).start();

As simple as making a function in JS!