How can I parse a String to BigDecimal?

java string parsing bigdecimal decimalformat
BenMansourNizar picture BenMansourNizar · Aug 14, 2013 · Viewed 217.7k times · Source

I have this String: 10,692,467,440,017.120 (it's an amount).

I want to parse it to a BigDecimal. The problem is that I have tried both DecimalFormat and NumbeFormat in vain.

Answer

René Link picture René Link · Aug 14, 2013

Try this

// Create a DecimalFormat that fits your requirements
DecimalFormatSymbols symbols = new DecimalFormatSymbols();
symbols.setGroupingSeparator(',');
symbols.setDecimalSeparator('.');
String pattern = "#,##0.0#";
DecimalFormat decimalFormat = new DecimalFormat(pattern, symbols);
decimalFormat.setParseBigDecimal(true);

// parse the string
BigDecimal bigDecimal = (BigDecimal) decimalFormat.parse("10,692,467,440,017.120");
System.out.println(bigDecimal);

If you are building an application with I18N support you should use DecimalFormatSymbols(Locale)

Also keep in mind that decimalFormat.parse can throw a ParseException so you need to handle it (with try/catch) or throw it and let another part of your program handle it

Related questions

How to convert/parse from String to char in java?

How do I parse a String value to a char type, in Java? I know how to do it to int and double (for example Integer.parseInt("123")). Is there a class for Strings and Chars?

Read More
In Java, how do I parse XML as a String instead of a file?

I have the following code: DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(xmlFile); How can I get it to parse XML contained within a String instead of a file?

Read More
How to check that a string is parseable to a double?

Is there a native way (preferably without implementing your own method) to check that a string is parseable with Double.parseDouble()?

Read More