Iteratively compute the Cartesian product of an arbitrary number of sets

akappa picture akappa · Nov 12, 2009 · Viewed 12.5k times · Source

I want to compute the cartesian product of an arbitrary number of nonempty sets in Java.

I've wrote that iterative code...

public static <T> List<Set<T>> cartesianProduct(List<Set<T>> list) {
    List<Iterator<T>> iterators = new ArrayList<Iterator<T>>(list.size());
    List<T> elements = new ArrayList<T>(list.size());
    List<Set<T>> toRet = new ArrayList<Set<T>>();
    for (int i = 0; i < list.size(); i++) {
        iterators.add(list.get(i).iterator());
        elements.add(iterators.get(i).next());
    }
    for (int j = 1; j >= 0;) {
        toRet.add(Sets.newHashSet(elements));
        for (j = iterators.size()-1; j >= 0 && !iterators.get(j).hasNext(); j--) {
            iterators.set(j, list.get(j).iterator());
            elements.set(j, iterators.get(j).next());
        }
        elements.set(Math.abs(j), iterators.get(Math.abs(j)).next());
    }
    return toRet;
}

...but I found it rather inelegant. Someone has a better, still iterative solution? A solution that uses some wonderful functional-like approach? Otherwise... suggestion about how to improve it? Errors?

Answer

Kevin Bourrillion picture Kevin Bourrillion · Nov 12, 2009

I've written a solution that doesn't require you to fill up a large collection in memory. Unfortunately, the code required is hundreds of lines long. You may have to wait until it appears in the Guava project (https://github.com/google/guava), which I hope will be by the end of the year. Sorry. :(

Note that you may not need such a utility if the number of sets you're cartesian-producting is a fixed number known at compile time -- you could just use that number of nested for loops.

EDIT: the code is released now.

Sets.cartesianProduct()

I think you'll be very happy with it. It only creates the individual lists as you ask for them; doesn't fill up memory with all MxNxPxQ of them.

If you want to inspect the source, it's here.

Enjoy!