I'm trying to learn, how spring security works, so I've downloaded some sample project and then I tried to implement that solution to my project. But when I try to login, I get 404
error and in an address bar I have http://localhost:8080/fit/j_spring_security_check
. I tried to look at similar questions here, but I wasn't able to realize, how to apply it to my project. I'd be really thankful, if somebody, who is more experienced, could help me.
My app structure looks like this:
applicationContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<context:annotation-config/>
<context:component-scan base-package="cz.cvut.fit"/>
<import resource="classpath:applicationContext-security.xml"/>
</beans>
applicationContext-web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<context:annotation-config/>
<context:component-scan base-package="cz.cvut.fit" />
<mvc:annotation-driven />
<security:global-method-security jsr250-annotations="enabled"
proxy-target-class="true"/>
</beans>
applicationContext-security.xml:
<beans xmlns:security="http://www.springframework.org/schema/security"
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<security:http pattern="/css/**" security="none"/>
<security:http pattern="/views/login.jsp*" security="none"/>
<security:http pattern="/views/denied.jsp" security="none"/>
<security:http auto-config="true" access-denied-page="/denied.jsp" servlet-api-provision="false">
<security:intercept-url pattern="/views/login.jsp*" access="IS_AUTHENTICATED_ANONYMOUSLY"/>
<security:intercept-url pattern="/views/edit/**" access="ROLE_EDIT"/>
<security:intercept-url pattern="/views/admin/**" access="ROLE_ADMIN"/>
<security:intercept-url pattern="/**" access="ROLE_USER"/>
<security:form-login login-page="/views/login.jsp" authentication-failure-url="/denied.jsp"
default-target-url="/home.jsp"/>
<security:logout/>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:user-service>
<security:user name="adam" password="adampassword" authorities="ROLE_USER"/>
<security:user name="jane" password="janepassword" authorities="ROLE_USER, ROLE_ADMIN"/>
<security:user name="sue" password="suepassword" authorities="ROLE_USER, ROLE_EDIT"/>
</security:user-service>
</security:authentication-provider>
</security:authentication-manager>
</beans>
You are trying to validate to a uri based on the current context path of the web page. the JSTL tag lib can be used to ensure you easily generate the correct urls based on the context of the application. You can do this by using a tag library if you want to get it implemented quickly. To do this you can add the jstl tag library to the top of the jsp:
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
Then you can use the following to post to the login servlet.
<form action="<c:url value="/j_spring_security_check"></c:url>" method="post" role="form">
This ensures you alway post to <your_application_context>/j_spring_security_check.
reference for jstl: http://docs.oracle.com/javaee/5/jstl/1.1/docs/tlddocs/c/url.html