Access file in WebContent folder from a servlet

java servlets apache-fop
jobinbasani picture jobinbasani · Sep 25, 2009 · Viewed 36.4k times · Source

I'm trying to generate a PDF document using FOP. The pdf generation code is kept in a servlet and the xsl is in a specific folder in the WebContent folder.

How can I access this xsl file by giving a relative path? It works only if I give the complete path in the File object.

I need to generate the xml content dynamically. How can I give this dynamically generated xml as the source instead of a File object?

Please provide your suggestions.

Answer

GBa picture GBa · Sep 25, 2009

To get the path you can just do:

String path = s.getServletContext().getRealPath("/WEB-INF/somedir/hdfeeh");

s is the class that implements HTTPServlet.You can also use this.getServletContext() if its your servlet class.

Then pass this as a parameter.

As far as using dynamically generated XML, the library you're using should support using an input stream, write your XML, convert it to a byte array, then wrap it in a ByteArrayInputStream and use this.

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