Am having a HTML page http://www.mywebapp.com/sample.html
which is used from remote server. am passing the HTML URL as hidden form like this in the same HTML form,
<form action="/myservlet?userid=12345" method="post" enctype="multipart/form-data">
<input type="file" name="file">
<input type="submit" value="Submit">
<input type="hidden" name="url" value="http://www.mywebapp.com/sample.html"/>
</form>
In my servlet i got the hidden URL http://www.mywebapp.com/sample.html
and stored it as
String fieldValue = http://www.mywebapp.com/sample.html
Now When i try RequestDispatcher
and forward the page to the hidden URL like this,
RequestDispatcher rd = req.getRequestDispatcher(fieldValue);
rd.forward(req, resp);
am getting ERROR 404
.
Can anyone suggest me an idea to solve this.
EDITED
What i exactly want to do is, From a Remote Server a HTML page will request to my REST Web services. The response of the web service will be in JSON output. Now i want to send this JSON Response to the requested HTML form(i.e. to the Remote Server HTML page)
Can anyone suggest an idea to solve this. Your help will be appreciated.
You can't forward a request to a URL which is external to your webapp. You probably want to send a redirect to this URL instead. See HttpServletResponse.sendRedirect()
.