JAXB marshalling Java to output XML file

Question

problem is how do i generate XML file output instead of system.out?

package jaxbintroduction;

import java.io.FileOutputStream;
import java.io.OutputStream;

public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        // TODO code application logic here
        itemorder.Book quickXML = new itemorder.Book();

        quickXML.setAuthor("Sillyme");
        quickXML.setDescription("Dummie book");
        quickXML.setISBN(123456789);
        quickXML.setPrice((float)12.6);
        quickXML.setPublisher("Progress");
        quickXML.setTitle("Hello World JAVA");

        try {            
            javax.xml.bind.JAXBContext jaxbCtx = javax.xml.bind.JAXBContext.newInstance(quickXML.getClass().getPackage().getName());
            javax.xml.bind.Marshaller marshaller = jaxbCtx.createMarshaller();
            marshaller.setProperty(javax.xml.bind.Marshaller.JAXB_ENCODING, "UTF-8"); //NOI18N
            marshaller.setProperty(javax.xml.bind.Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
            marshaller.marshal(quickXML, System.out);
            OutputStream os = new FileOutputStream( "nosferatu.xml" );
            marshaller.marshal( quickXML, os );

        } catch (javax.xml.bind.JAXBException ex) {
            // XXXTODO Handle exception
            java.util.logging.Logger.getLogger("global").log(java.util.logging.Level.SEVERE, null, ex); //NOI18N
        }
    }

}

Answer 1

If you are using a JAXB 2.1 or greater then you can marshal directly to a java.io.File object:

 File file = new File( "nosferatu.xml" );
 marshaller.marshal( quickXML, file );

Corrsponding Javadoc

• http://docs.oracle.com/javase/6/docs/api/javax/xml/bind/Marshaller.html#marshal%28java.lang.Object,%20java.io.File%29