How to pass local filename to ClassPathXmlApplicationContext?

Dims picture Dims · Nov 1, 2012 · Viewed 35.4k times · Source

By "local filename" I mean that resource file is located in the same directory as class file. In the case below this is JUnitRunner.class file. Java's getResource() file can handle this if path does not start with /'

I can't figure out, how to do the same ClassPathXmlApplicationContext constructor?


package springtests;

import java.io.File;
import java.net.URISyntaxException;
import java.net.URL;

import org.junit.Test;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class JUnitRunner {

    private final static Logger log = LoggerFactory.getLogger(JUnitRunner.class);

    @Test
    public void test() throws URISyntaxException {

        String filename = "test01.xml";

        URL url = getClass().getResource(filename);


        File file = new File(url.toURI());
        log.info("File exists: {}", file.exists());

        try {
            new ClassPathXmlApplicationContext(filename);
        }
        catch(Exception e) {
            log.error("Can't load context", e);
        }

    }
}

the output follows

15:32:27,375 3    [main] INFO  springtests.JUnitRunner  - File exists: true
15:32:27,422 50   [main] INFO  org.springframework.context.support.ClassPathXmlApplicationContext  - Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@ee3aa7: startup date [Thu Nov 01 15:32:27 MSK 2012]; root of context hierarchy
15:32:27,475 103  [main] INFO  org.springframework.beans.factory.xml.XmlBeanDefinitionReader  - Loading XML bean definitions from class path resource [test01.xml]
15:32:27,477 105  [main] ERROR springtests.JUnitRunner  - Can't load context
org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [test01.xml]; nested exception is java.io.FileNotFoundException: class path resource [test01.xml] cannot be opened because it does not exist
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:341)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:302)

...

UPDATE

XML file is located in the same folder as class file. It is visible from the fact that getResource() see it.

Answer

Augusto picture Augusto · Nov 1, 2012

I don't properly understand what is that you're asking, but have you tried:

new ClassPathXmlApplicationContext("classpath*:test01.xml");

That will search in all the classpath for test01.xml. You can read more about this in the Spring resources documentation page.