Check if string ends with certain pattern

java regex string pattern-matching
The Learner picture The Learner · Sep 7, 2012 · Viewed 147k times · Source

If I have a string like:

This.is.a.great.place.too.work.

or:

This/is/a/great/place/too/work/

than my program should give me that the sentence is valid and it has "work".


If I Have :

This.is.a.great.place.too.work.hahahha

or:

This/is/a/great/place/too/work/hahahah

then my program should not give me that there is a "work" in the sentence.


So I am looking at java strings to find a word at the end of the sentence having . or , or / before it. How can I achieve this?

Answer

pb2q picture pb2q · Sep 7, 2012

This is really simple, the String object has an endsWith method.

From your question it seems like you want either /, , or . as the delimiter set.

So:

String str = "This.is.a.great.place.to.work.";

if (str.endsWith(".work.") || str.endsWith("/work/") || str.endsWith(",work,"))
     // ...

You can also do this with the matches method and a fairly simple regex:

if (str.matches(".*([.,/])work\\1$"))

Using the character class [.,/] specifying either a period, a slash, or a comma, and a backreference, \1 that matches whichever of the alternates were found, if any.

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