Mockito: Trying to spy on method is calling the original method

Dave picture Dave · Jul 23, 2012 · Viewed 234.1k times · Source

I'm using Mockito 1.9.0. I want mock the behaviour for a single method of a class in a JUnit test, so I have

final MyClass myClassSpy = Mockito.spy(myInstance);
Mockito.when(myClassSpy.method1()).thenReturn(myResults);

The problem is, in the second line, myClassSpy.method1() is actually getting called, resulting in an exception. The only reason I'm using mocks is so that later, whenever myClassSpy.method1() is called, the real method won't be called and the myResults object will be returned.

MyClass is an interface and myInstance is an implementation of that, if that matters.

What do I need to do to correct this spying behaviour?

Answer

Tomasz Nurkiewicz picture Tomasz Nurkiewicz · Jul 23, 2012

Let me quote the official documentation:

Important gotcha on spying real objects!

Sometimes it's impossible to use when(Object) for stubbing spies. Example:

List list = new LinkedList();
List spy = spy(list);

// Impossible: real method is called so spy.get(0) throws IndexOutOfBoundsException (the list is yet empty)
when(spy.get(0)).thenReturn("foo");

// You have to use doReturn() for stubbing
doReturn("foo").when(spy).get(0);

In your case it goes something like:

doReturn(resulstIWant).when(myClassSpy).method1();