Java mail sender's address displayed rather than his name

Nelo Angelo picture Nelo Angelo · Jun 26, 2012 · Viewed 55.5k times · Source

I am trying to send mail to my friends through my Java Mail application. I am able to do it successfully however the receiver's column in the mailbox shows the complete email address rather than the name of the sender. I tried changing various parameters but still the mailbox would show the full e-mail address rather than the name of the sender.

using this method to send the message:

 public void send(String key){
    String to=key;
    String from="mygmailid";
    String subject="wassp";
    String text="Hello";
    Properties props=new Properties();

    props.put("mail.smtp.host", "smtp.gmail.com");
    props.put("mail.smtp.user", "myname");
    props.put("mail.smtp.socketFactory.port", "465");
    props.put("mail.smtp.socketFactory.class","javax.net.ssl.SSLSocketFactory");
    props.put("mail.smtp.auth", "true");
    props.put("mail.smtp.port", "465");
    Session mailSession=Session.getDefaultInstance(props);
    Message simpleMessage=new MimeMessage(mailSession);

    InternetAddress fromAddress=null;
    InternetAddress toAddress=null;

    try{
        fromAddress=new InternetAddress(from);
        toAddress=new InternetAddress(to);
    }
    catch(AddressException e){
        e.printStackTrace();
    }

    try{
        simpleMessage.setFrom(fromAddress);
        simpleMessage.setRecipient(RecipientType.TO,toAddress);
        simpleMessage.setSubject(subject);
        simpleMessage.setText(text);

        transport.connect("smtp.gmail.com",465, "[email protected]", "mygmailpassword");
        transport.sendMessage(simpleMessage, simpleMessage.getAllRecipients());
        transport.close();  

    }
    catch(MessagingException e){
        e.printStackTrace();
    }
}

I am calling this method as:

public static void main(String[] args) {
    MailSender mailer=new MailSender();
    mailer.send("[email protected]");
}

Answer

Raghav picture Raghav · Jun 26, 2012

You can set a name in the InternetAddress using

new InternetAddress("[email protected]", "Your Name");