Remove Elements from a HashSet while Iterating

Scott picture Scott · Jul 10, 2009 · Viewed 127.5k times · Source

So, if I try to remove elements from a Java HashSet while iterating, I get a ConcurrentModificationException. What is the best way to remove a subset of the elements from a HashSet as in the following example?

Set<Integer> set = new HashSet<Integer>();

for(int i = 0; i < 10; i++)
    set.add(i);

// Throws ConcurrentModificationException
for(Integer element : set)
    if(element % 2 == 0)
        set.remove(element);

Here is a solution, but I don't think it's very elegant:

Set<Integer> set = new HashSet<Integer>();
Collection<Integer> removeCandidates = new LinkedList<Integer>();

for(int i = 0; i < 10; i++)
    set.add(i);

for(Integer element : set)
    if(element % 2 == 0)
        removeCandidates.add(element);

set.removeAll(removeCandidates);

Thanks!

Answer

Adam Paynter picture Adam Paynter · Jul 10, 2009

You can manually iterate over the elements of the set:

Iterator<Integer> iterator = set.iterator();
while (iterator.hasNext()) {
    Integer element = iterator.next();
    if (element % 2 == 0) {
        iterator.remove();
    }
}

You will often see this pattern using a for loop rather than a while loop:

for (Iterator<Integer> i = set.iterator(); i.hasNext();) {
    Integer element = i.next();
    if (element % 2 == 0) {
        i.remove();
    }
}

As people have pointed out, using a for loop is preferred because it keeps the iterator variable (i in this case) confined to a smaller scope.