Simple way to find if two different lists contain exactly the same elements?

Question

What is the simplest way to find if two Lists contain exactly the same elements, in the standard Java libraries?

It shouldn't matter if the two Lists are the same instance or not, and it shouldn't matter if the type parameter of the Lists are different.

e.g.

List list1
List<String> list2; 
// ... construct etc

list1.add("A");
list2.add("A"); 
// the function, given these two lists, should return true

There's probably something staring me in the face I know :-)

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EDIT: To clarify, I was looking for the EXACT same elements and number of elements, in order.

Answer 1

If you care about order, then just use the equals method:

list1.equals(list2)

From the javadoc:

Compares the specified object with this list for equality. Returns true if and only if the specified object is also a list, both lists have the same size, and all corresponding pairs of elements in the two lists are equal. (Two elements e1 and e2 are equal if (e1==null ? e2==null : e1.equals(e2)).) In other words, two lists are defined to be equal if they contain the same elements in the same order. This definition ensures that the equals method works properly across different implementations of the List interface.

If you want to check independent of order, you could copy all of the elements to Sets and use equals on the resulting Sets:

public static <T> boolean listEqualsIgnoreOrder(List<T> list1, List<T> list2) {
    return new HashSet<>(list1).equals(new HashSet<>(list2));
}

A limitation of this approach is that it not only ignores order, but also frequency of duplicate elements. For example, if list1 was ["A", "B", "A"] and list2 was ["A", "B", "B"] the Set approach would consider them to be equal.

If you need to be insensitive to order but sensitive to the frequency of duplicates you can either:

• sort both lists (or copies) before comparing them, as done in this answer to another question
• or copy all elements to a Multiset