I have to open a .exe file from my Java program. So I tried following code First.
Process process = runtime.exec("c:\\program files\\test\\test.exe");
But I was getting some error. Then I found out that the exe has to be launched from that location that is c://program files/test/ only then it will open with out errors. So I decided to write a .bat file and execute so that it will cd to that location and execute the .exe file.
Following is my code:
BufferedWriter fileOut;
String itsFileLocation = "c:\\program files\\test\\"
System.out.println(itsFileLocation);
try {
fileOut = new BufferedWriter(new FileWriter("C:\\test.bat"));
fileOut.write("cd\\"+"\n");
fileOut.write("cd "+ itsFileLocation +"\n");
fileOut.write("test.exe"+"\n");
fileOut.write("exit"+"\n");
fileOut.close(); // Close the output stream after all output is done.
} catch (IOException e1) {
e1.printStackTrace();
} // Create the Buffered Writer object to write to a file called filename.txt
Runtime runtime = Runtime.getRuntime();
try {
Process process =runtime.exec("cmd /c start C:\\test.bat");
} catch (IOException e) {
e.printStackTrace();
}
The above code works perfectly. However, the command prompt is also opened at the back of my .exe (Application). It closes only after the .exe file exits..
I need to clse my command prompt when my application stats.
My .bat file will be like following after it is written by the program.
cd\
cd C:\Program Files\test\
test.exe
exit
You don't need a console. You can execute a process using a working directory:
exec(String command, String[] envp, File dir)
Executes the specified string command in a separate process with the specified environment and working directory.
With respect to your code it should be...
Runtime.getRuntime().exec("c:\\program files\\test\\test.exe", null, new File("c:\\program files\\test\\"));