I have some sliders in my application that allows the user to change ARGB colors, however I need to convert these values to a hex value like 0xff000000, which is solid black.
This is what I have so far:
protected int toHex(Color col) {
String as = pad(Integer.toHexString(col.getAlpha()));
String rs = pad(Integer.toHexString(col.getRed()));
String gs = pad(Integer.toHexString(col.getGreen()));
String bs = pad(Integer.toHexString(col.getBlue()));
String hex = "0x" + as + rs + gs + bs;
return Integer.parseInt(hex, 16);
}
private static final String pad(String s) {
return (s.length() == 1) ? "0" + s : s;
}
However upon getting the Integer value like below, I get a NumberFormatException for input string: "0xccffffff":
int color = toHex(new Color(153f, 153f, 153f, 0.80f));
Any ideas on how to get this to an Integer? Thanks.
The Color parameters must be floats between 1f and 0f. So this is a valid color:
int color = toHex(new Color(1f, 1f, 1f, 1f));
Which is white.