Create a BufferedImage from file and make it TYPE_INT_ARGB

user1319734 picture user1319734 · May 1, 2012 · Viewed 129.7k times · Source

I have a PNG file with transparency that is loaded and stored in a BufferedImage. I need this BufferedImage to be of TYPE_INT_ARGB. However, when I use getType() the returned value is 0 (TYPE_CUSTOM) instead of 2 (TYPE_INT_ARGB).

This is how I load the .png:

public File img = new File("imagen.png");

public BufferedImage buffImg = 
    new BufferedImage(240, 240, BufferedImage.TYPE_INT_ARGB);

try { 
    buffImg = ImageIO.read(img ); 
} 
catch (IOException e) { }

System.out.Println(buffImg.getType()); //Prints 0 instead of 2

How can I load the .png, save in the BufferedImage and make it TYPE_INT_ARGB?

Answer

Jeffrey picture Jeffrey · May 1, 2012
BufferedImage in = ImageIO.read(img);

BufferedImage newImage = new BufferedImage(
    in.getWidth(), in.getHeight(), BufferedImage.TYPE_INT_ARGB);

Graphics2D g = newImage.createGraphics();
g.drawImage(in, 0, 0, null);
g.dispose();