How to prompt user to turn on Location Services...again

toofah picture toofah · May 14, 2011 · Viewed 25.5k times · Source

I want to have the same functionality as the Map app, where user is prompted every time they press the 'current location' button to turn on their Location Services if they are off:

  • Turn off location services
  • User presses 'getCurrentLocation' button
  • App tries to get location using CLLocationManager
  • User gets 'Turn On Location Services..." message that shows "Settings" and "Cancel" buttons.
  • User taps 'Cancel'
  • User presses ''getCurrentLocation' button again
  • App tries to get location using CLLocationManager again
  • User does not get 'Turn On Location Services..." message any more

In the Map app, the user gets "Turn On Location Services..." message every time. How can I get my app to do the same? I made user I am using a new instance of CLLocationManager, in case that was the problem, but it was not. I can't see any settings that would affect this.

If I make my own Alert I cannot get the same 'Settings' button functionality. Also, I don't want the user to see multiple Alerts that look the same.

Any ideas?

Answer

Aaron Wasserman picture Aaron Wasserman · Sep 10, 2014

New in iOS 8 there is a constant called UIApplicationOpenSettingsURLString.

From the "What's new in iOS" document under UIKit is the line:

You can take the user directly to your app-related settings in the Settings app. Pass the UIApplicationOpenSettingsURLString constant to the openURL: method of the UIApplication class.

From Apple's documentation:

UIApplicationOpenSettingsURLString

Used to create a URL that you can pass to the openURL: method. When you open the URL built from this string, the system launches the Settings app and displays the app’s custom settings, if it has any.

You can pass this into the UIApplication openURL: method. It might look something like:

NSURL *settings = [NSURL URLWithString:UIApplicationOpenSettingsURLString];

if ([[UIApplication sharedApplication] canOpenURL:settings])
    [[UIApplication sharedApplication] openURL:settings];