I override NSURLProtocol and need to return HTTP response with specific statusCode. NSHTTPURLResponse does not have statusCode setter, so I tried to override it with:
@interface MyHTTPURLResponse : NSHTTPURLResponse {}
@implementation MyHTTPURLResponse
- (NSInteger)statusCode {
return 200; //stub code
}
@end
Overridden startLoading method of NSURLProtocol looks like this:
-(void)startLoading
{
NSString *url = [[[self request] URL] absoluteString];
if([url isEqualToString:SPECIFIC_URL]){
MyURLResponse *response = [[MyURLResponse alloc] initWithURL:[NSURL URLWithString:@"http://fakeUrl"]
MIMEType:@"text/plain"
expectedContentLength:0 textEncodingName:nil];
[[self client] URLProtocol:self
didReceiveResponse:response
cacheStoragePolicy:NSURLCacheStorageNotAllowed];
[[self client] URLProtocol:self didLoadData:[@"Fake response string"
dataUsingEncoding:NSASCIIStringEncoding]];
[[self client] URLProtocolDidFinishLoading:self];
[response release];
}
else{
[NSURLConnection connectionWithRequest:[self request] delegate:self];
}
}
But this approach does not work, the response created in NSURLProtocol is always with statusCode = 0 on web page. At the same time responses that are returned from network by NSURLConnection have normal expected statusCodes.
Can anyone please help with ideas how to set statusCode explicitly for created NSURLResponse? Thanx.
Here is a better solution.
On iOS 5.0 and up you don't have to do anything crazy with private APIs or overloading NSHTTPURLResponse
anymore.
To create an NSHTTPUTLResponse
with your own status code and headers, you can now simply use:
initWithURL:statusCode:HTTPVersion:headerFields:
Which is not documented in the generated documentation but is actually present in the NSURLResponse.h
header file and also marked as a public API that is available on OS X 10.7 and iOS 5.0.
Also note that if you are using the NSURLProtocol
trick to make XMLHTTPRequest
calls from a UIWebView
, that you will need to set the Access-Control-Allow-Origin
header appropriately. Otherwise the XMLHTTPRequest
security kicks in and even though your NSURLProtocol
will receive and handle the request, you will not be able to send a response back.