As I understand, in Objective-C you can only put Objects into dictionaries. So if I was to create a dictionary, it would have to have all objects. This means I need to put my ints in as NSNumber, right?
SOo...
NSNumber *testNum = [NSNumber numberWithInt:varMoney];
NSMutableDictionary *dictionary = [[NSMutableDictionary alloc] init];
[dictionary setObject:@"OMG, Object 1!!!!" forKey:@"1"];
[dictionary setObject:@"Number two!" forKey:@"2"];
[dictionary setObject:testNum forKey:@"3"];
NSNumber *retrieved = [dictionary objectForKey:@"3"];
int newVarMoney = [retrieved intValue];
Where varMoney is an int that has been declared earlier. My question is, is there a better way to store "int" in a dictionary than putting it into a NSNumber?
Thanks!
Edit: 04/25/13
It's been a long time since I asked this question. For people stumbling on it in the future, there are easier ways to do this with the Apple LLVM Compiler 4.0, which has been default in Xcode for a bit. (ARC)
NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
[dictionary setObject:@1337 forKey:@"1"];
That's it, use the @1337 Syntax to quickly create NSNumber objects. Works with Variables, so my above could become:
[dictionary setObject:@(varMoney) forKey:@"3"];
or
dictionary[@"mykey"] = @1337;
Simpler.
You are correct, NSNumber
is the normal way to handle this situation. You can use NSValue
or NSDecimalNumber
, too.