how to call a method of multiple arguments with delay

ios methods selector
Frade picture Frade · Mar 9, 2012 · Viewed 36.4k times · Source

I'm trying to call a method after some delay.

I know there is a solution for that:

[self performSelector:@selector(myMethod) withObject:nil afterDelay:delay];

I saw this question and Documentation

But my question is: How can I call a method that takes two parameters??

for instance:

- (void) MoveSomethigFrom:(id)from To:(id)to;

How would I call this method with delay, using performSelector:withObject:afterDelay:

Thanks

Answer

Martin Ullrich picture Martin Ullrich · Mar 9, 2012

use dispatch_after:

double delayInSeconds = 2.0;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
    //code to be executed on the main queue after delay
    [self MoveSomethingFrom:from To:to];
});

EDIT 2015: For Swift, i recommend using this small helper method: dispatch_after - GCD in swift?

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